Question

Rohit sold a chair and a table together for rupees 1520 thereby making a profit of 25% on the chair and 10% on table. By selling them together for rupees 1535 he would have made a profit of 10% on the chair and 25% On the table. Find the cost price of each.

Answer 1

2nd equation......

first step
let tge chair C.P = x
and table C. P = y
$x + \frac{25x}{100} + y + \frac{10y}{100} = 1520 \\ \frac{5x}{4} + \frac{11y}{10} = 1520 \\ 100x + 88y = 1520 \times 80 \\ 50x + 44y = 1520 \times 40 \\ 50x + 44y = 60800 \\ 25x + 22y = 30400 \: \: \: \: \: equation \: \: (1)$

Answer 2

Here your answer

Let the cost price of chair = x.

Let the cost price of table = y.

Condition 1:

Profit on the chair = 25%.

Selling price of chair = x + 25x/100

= 125x/100.

Profit on the table = 10%.

Selling price of table = x + 10/100

= 110x/100.

Given that Total selling price = 1520

125x/100 + 110x/100 = 1520

125x + 110x = 1520 * 100

125x + 110x = 152000

25x + 22y = 30400 ------------------------ (1)

Condition 2:

Profit on the chair =10%.

Selling price of the chair = x + 10x/100

= 110x/100

Profit on the table = 25%

Selling price of the table = y + 25y/100

= 125y/100.

Given that total selling price = 1535

110x/100 + 125y/100 = 1535

110x + 125y = 153500

22x + 25y = 30700 --------------------------- (2)

On solving (1) * 22 & (2) * 25, we get

550x + 484y = 668800

550x + 625y = 767500

------------------------------------

-141y = -98700

y = 700.

Substitute y = 700 in (2), we get

22x + 25y = 30700

22x + 25 * 700 = 30700

22x + 17500 = 30700

22x = 13200

x = 13200/22

x = 600.

Therefore the cost price of chair = 600 rupees.

the cost price of table = 700 rupees.

Hope this helps! -----------------