Rohit was putting up one of his paintings in his living room. Before this Rohit had put a
grid on the wall where each unit measured equal to a foot. The upper-left corner of the frame is at point C (1, 8) and the upper-right corner at D (7, 8). The bottom-left corner is at A (1, 2) and the bottom-right corner at B (7, 2).
Answers
Answer:
The ans is
Step-by-step explanation:
Given : Frame with coordinates
upper left corner : (1 , 8)
upper right corner : (7, 8)
bottom left corner : (1, 2)
bottom right corner : (7, 2)
Solution :
1. Find width of the painting
Width of the painting = distance between upper left corner and upper right corner
By using distance formula,
∵ Width of the painting = (x2 - x1) + (y2 - y1)
∵ Width of the painting = (7 - 1) + (8 - 8)
∵ Width of the painting = 6 units.
2. Find the length of the painting
length of the painting = distance between upper left corner and bottom left corner
By using distance formula,
∵ Length of the painting = (x2 - x1) + (y2 - y1)
∵ Length of the painting = (1 - 1) + (8 - 2)
∵ Length of the painting = 6 units.
3. Side AB and CD are parallel to x axis.
4. Side AC and BD are parallel to y axis.
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Concept:
The study of geometry using coordinate points is known as coordinate geometry (also known as analytical geometry). It is possible to determine the separation between two points, divide a line into m:n segments, locate a line's midpoint, determine the area of a triangle in the Cartesian plane, and perform other operations using coordinate geometry.
The four quadrants are represented as
Quadrant 1 : (+x, +y)
Quadrant 2 : (-x, +y)
Quadrant 3 : (-x, -y)
Quadrant 4 : (+x, -y)
Distance between two points = √(x₂ - x₁)² +(y₂ - y₁)²
Given :
Frame with coordinates
upper left corner : (1 , 8)
upper right corner : (7, 8)
bottom left corner : (1, 2)
bottom right corner : (7, 2)
Find:
1)Find the width of the painting
2) Find the length of the painting
3) Sides which are parallel to x axis
4) Sides which are parallel to y-axis
Solution :
1. Find width of the painting
Width of the painting = distance between upper left corner and upper right corner
By using distance formula,
∵ Width of the painting = (x2 - x1) + (y2 - y1)
∵ Width of the painting = (7 - 1) + (8 - 8)
∵ Width of the painting = 6 units.
2. Find the length of the painting
length of the painting = distance between upper left corner and bottom left corner
By using distance formula,
∵ Length of the painting = (x2 - x1) + (y2 - y1)
∵ Length of the painting = (1 - 1) + (8 - 2)
∵ Length of the painting = 6 units.
3. Side AB and CD are parallel to x axis.
4. Side AC and BD are parallel to y axis.
#SPJ3