Question

Root 13-root6÷ root 13+root6

Answer 1

Answer:

$\frac{ \sqrt{13} - \sqrt{6} }{ \sqrt{13} + \sqrt{6} } = (\frac{ \sqrt{13} - \sqrt{6} }{ \sqrt{13} + \sqrt{6} } ) \times (\frac{ \sqrt{13} - \sqrt{6} }{ \sqrt{13} - \sqrt{6} } )$

$= \frac{ (\sqrt{13} - \sqrt{6} ) {}^{2} }{ { \sqrt{13} }^{2} - { \sqrt{6} }^{2} }$

$\frac{13 + 6 - 2 \sqrt{78} }{13 - 6}$

$\frac{19 - 2 \sqrt{78} }{7}$

may help you dear...✌❤

Answer 2

Step-by-step explanation:

solution:-√13-√6/√13+√6

=√13-√6/√13+√6*√13-√6/√13-√6

=(√13-√6)²/(√13)²-(√6)²

=(√13)²-2*√13*√6+(√6)²/13-6

=169-2√78+6/7

=175-2√78/7 ans

I hope it helps you

Plz... mark Brainliest