root 2 and 1/3 are sum and product of zeroes find polynomial
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Answered by
1
Answer:
-2 and -1/3
Step-by-step explanation:
x+2=0
x =-2
y+1/3=0
y=-1/3 I hope it helps you please mark as brainliest answer
Answered by
2
Answer:
Sum = root 2
Product = 1/3
The required polynomial is in the form = x^2 + (sum of zeroes)x - (product of zeroes)
= x^2 + root2 -1/3
Take Lcm as 3,
(3x^2 + 3root2 -1)/3
Let k = 1/3
k (3x^2 + 3root2 -1)
Hope this helps you.......................
Plz mark me the brainliest
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