Math, asked by sommyasingh, 1 year ago

root 2 minus root 3 upon 3 root 2 minus 2 root 3

Answers

Answered by Panzer786
9
Hii friend,

✓2 - ✓3 / 3✓2 - 2✓3

=> ✓2-✓3/3✓2 -2✓3 × 3✓2+2✓3/3✓2+2✓3

=> (✓2-✓3)(3✓2+2✓3)/(3✓2 - 2✓3)(3✓2+2✓3)

=> ✓2(3✓2+2✓3)-✓3(3✓2+2✓3)/(3✓2)²-(2✓3)²

=> 3×2 + 2✓6 -3✓6 - 2 × 3/ 18 - 12

=> 6+2✓6-3✓6-6/6

=> -✓6/6 ......Ans.....

HOPE IT WILL HELP YOU..... :-)
Answered by ria113
2
Heya !!

Here's your answer.. ⬇⬇

 =  \frac{ \sqrt{2}  -  \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3}  }  \\  \\   =  \frac{ \sqrt{2} -  \sqrt{3}  }{3 \sqrt{2} - 2 \sqrt{3}  }  \times  \frac{3 \sqrt{2} + 2 \sqrt{3}  }{3 \sqrt{2} + 2 \sqrt{3}  }  \\  \\  =  \frac{ \sqrt{2}(3 \sqrt{2} + 2 \sqrt{3}  ) -  \sqrt{3}(3 \sqrt{2}  + 2 \sqrt{3}  ) }{ ({3 \sqrt{2} }^{2}) - ( {2 \sqrt{3} }^{2})  }  \\  \\  =  \frac{6 + 2 \sqrt{6} - 3 \sqrt{6} - 6  }{18 - 12}  \\  \\  =  \frac{ -  \sqrt{6} }{6}  \\  \\
HOPE IT HELPS..

THANKS ^-^

abhi569: It should (3√2)² not (3√2²)
abhi569: Like that... It should be
abhi569: (2√3)² is not (2√3²)
abhi569: (-:
abhi569: Sorry for disturbing you
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