root 2xsquare + 7x +5root2 find the zeroes of the polynomial
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Answer:
2x^2+7x+5√2=0
(√2x^2+5x)+(2x+5√2)=0
√2x(√2x+5)+√2(√2x+5)=0
(√2x+5)(√2x+√2)=0
√2x+5=0 √2x+√2=0
√2x=-5 √2x=-√2
x=-5/√2 x=-√2/√2
x=-1
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