Question

Root 2y square-3y-2root2 =0.solve it using splitting middle term

Answer 1

Answer:

(√2y + 1)( y - 2√2) = 0

Step-by-step explanation:

Equation : √2y² - 3y - 2√2 = 0

Step 1: Multiply first and last term.

√2 × -2√2 = -2 × 2 = -4

Step 2: Divide the middle term such that on multiplying its parts the product is -4.

-3 = -4 + 1 [-4 × 1 = -4]

Now we solve the equation.

√2y² - 3y - 2√2 = 0

⇒√2y² - 4y + 1y - 2√2 = 0

⇒√2y² - (2 × √2 × √2)y + y - 2√2 = 0

⇒√2y ( y - 2√2) + 1(y - 2√2) = 0

⇒(√2y + 1)( y - 2√2) = 0

I suggest that you use quadratic formula. This method is a bit confusing.