Question

Root 3 - root 2 divide by root 3 + root 2

Answer 1

i have rationalised the denominator...

hope it helps...

Answer 2

Privet Mate ,

There your answer is......,

$=\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

$=\frac{ (\sqrt{3} - \sqrt{2}) {}^{2} }{ (\sqrt{3} ) {}^{2} - ( \sqrt{2} ) {}^{2} }$

$= \frac{ (\sqrt{3} ) {}^{2} + { \sqrt{2} }^{2} - 2 \times \sqrt{3} \times \sqrt{2} }{ 3 - 2}$

$= 3 + 2 - 2 \sqrt{6}$

$= 5 - 2 \sqrt{6}$

Gracias Mate....✌️

❤️ Hope it may helps u....☺️❤️