Question

root 3 sin 0 - cos 0 = 0 and 0°<O< 90°, find the value of theta​

Answer 1

Answer:

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Step-by-step explanation:

ANSWER

We have,

3

sinθ−cosθ=0

3

sinθ=cosθ

3

=

sinθ

cosθ

3

=cotθ

tanθ=

3

1

tanθ=tan

6

π

θ=nπ+

6

π

where n ε Z

Hence, this is the answer.

Answer 2

Given:

√3sinθ - cosθ = 0

To Find.

Value of θ =?

solution:

solve the question we transfer the cos θ on the other side of the equal to with which we get

$\sf\green{√3sinθ - cosθ = 0}$

$\sf\green{√3sinθ = cosθ}$

$\sf\green{√3 = \frac{cosθ}{sinθ}}$

$\sf\green{√3 = cotθ }$

$\sf\green{30° = cotθ }$

Hence, the value of θ is proved to be 30, now the question says the θ is between zero degree and 90 degree thereby, proving that the value of

$\sf\green{θ = 30° }$

.