Question

root 3 X square + 10 X + 7 root 3 verify the relation between the zeros and coefficients​

Answer 1

Solution:

Given quadratic expression:

√3x²+10x+7√3

Splitting the middle term,we get

= √3x²+3x+7x+7√3

= √3x(x+√3)+7(x+√3)

= (x+√3)(√3x+7)

To find the zeroes of the expression, we must take

(x+√3)(√3x+7) = 0

=> x+√3 = 0 or √3x+7 = 0

=> x = -√3 or x = -7/√3

Therefore,

m = -√3 , n = -7/√3 are zeroes of given Quadratic expression.

verification:

Compare √3x²+10x+7√3 with

ax²+bx+c , we get

a=√3 , b = 10, c = 7√3

i) Sum of the zeroes

= m+n

= -√3+ (-7/√3)

= (-3-7)/√3

= -10/√3

= - b/a

ii) Product of the zeroes

= mn

= (-√3)×(-7/√3)

= 7/1

= c/a = (constant/x²-coefficient)

••••

Answer 2

Answer:

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