Question

root(3x+1) - root(x-1) =2​

Answer 1

Answer:

$(\sqrt{3x + 1} ) - ( \sqrt{x - 1 } ) = 2$

$\sqrt{3x + 1 - x + 1} = 2$

$\sqrt{2x + 2} = 2$

$2x + 2 = {2}^{2}$

$2x = 4 - 2 \\ 2x = 2$

$x = 1$