root 3xsquare +10x +7root 3 find the zeroes of each of the following polynomials and verify the relation between zeroes and its coefficient
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Hola there,
=> √3x² + 10x + 7√3
=> √3x² + 3x + 7x + 7√3
=> √3x(x + √3) + 7(x + √3)
=> (x + √3)(√3x + 7) = 0
=> x = -√3 and -7√3/3
Zeroes of polynomial = -√3 , -7√3/3
Verification.
a = √3
b = 10
c = 7√3
Alpha + beta = -√3 + (-7/√3) = (-3 - 7)/√3
= -10/√3
= -b/a
= -10/√3
= cofficient of x/ cofficient of x²
Alpha×beta = -√3×(-7/√3)
= 7
= c/a
= 7√3/√3
= 7
= constant term/cofficient of x²
Hope this helps...:)
=> √3x² + 10x + 7√3
=> √3x² + 3x + 7x + 7√3
=> √3x(x + √3) + 7(x + √3)
=> (x + √3)(√3x + 7) = 0
=> x = -√3 and -7√3/3
Zeroes of polynomial = -√3 , -7√3/3
Verification.
a = √3
b = 10
c = 7√3
Alpha + beta = -√3 + (-7/√3) = (-3 - 7)/√3
= -10/√3
= -b/a
= -10/√3
= cofficient of x/ cofficient of x²
Alpha×beta = -√3×(-7/√3)
= 7
= c/a
= 7√3/√3
= 7
= constant term/cofficient of x²
Hope this helps...:)
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