Question

root 5+root3 whole divided by root80+root48-,root27-root45

Answer 1

5√+3√80√+48√−45√−27√= 5√+3√4×4×5√+4×4×3√−3×3×5√−3×3×3√= 5√+3√45√+43√−35√−33√= 5√+3√(45√−35√)+(43√−33√)= 5√+3√5√+3√= 1

Answer 2

Answer:

$\frac{\sqrt{5}+\sqrt{3}}{\sqrt{80}+\sqrt{48}-\sqrt{27}-\sqrt{45}}=1$

Step-by-step explanation:

Given : $\frac{\sqrt{5}+\sqrt{3}}{\sqrt{80}+\sqrt{48}-\sqrt{27}-\sqrt{45}}$

To Find : Solve the expression

Solution :

$\sqrt{5}=2.236$

$\sqrt{3}=1.732$

$\sqrt{80}=8.944$

$\sqrt{48}=6.928$

$\sqrt{27}=5.196$

$\sqrt{45}=6.708$'

$\frac{\sqrt{5}+\sqrt{3}}{\sqrt{80}+\sqrt{48}-\sqrt{27}-\sqrt{45}}$

$\frac{2.236+1.732}{8.944+6.928-5.196-6.708}$

$1$

Hence $\frac{\sqrt{5}+\sqrt{3}}{\sqrt{80}+\sqrt{48}-\sqrt{27}-\sqrt{45}}=1$