Question

Root 6 in number line

Answer 1

We have to construct √6 on the number line.

Steps:

1. Draw a horizontal line.

2. Now take a point A on the line and mark at pint B so that AB = 6 unit

3. From the point B, mark C such that BC = 1

4. Now take a point O in between A and B such that OA = OC = (6 + 1)/2 = 7/3 = 3.5 unit

5. Now draw a circle having center at O and radius 3.5 units.

6. Draw a perpendicular to AC passing through B and intersecting the semicircle at D.

7. With B as center and BD as redius, draw a circle such that it meets the number line at E.

Now, BE represents √6 on the number line which shown in the given figure.



Answer 2

Hi!

Here is the answer to your question.

 

Draw a number line (l) and mark the points O, A and B such that OA = AB = 1. Draw BC⊥ l such that BC = 1 units. Join OC



Cheers!