Question

root 6 minus root 3​

Answer 1

Step-by-step explanation:

root 6 minus root 3 = root 3

Answer 2

Given: $\sqrt{6} -\sqrt{3}$

Solution:

Now, $\sqrt{6} -\sqrt{3\\}$

•    = $\sqrt{3} .\sqrt{2} -\sqrt{3}$ , c; early an irrational number since both $\sqrt{2}$ and $\sqrt{3$ are irrational.
• The conjugate of this irrational number is $\sqrt{6} + \sqrt{3}$ that they give a rational value when we find their product.

Hence, $\sqrt{6} + \sqrt{3}$ is irrational.