Question

root ( 8⁰+2/3) = (0.6)^2-3x​

Answer 1

Anѕwєr :-

$\sqrt{8° + \frac{2}{3} } \: = \: (0.6)^{2 - 3x} \\ \\ \\ \implies{ \sqrt{1 + \frac{2}{3} } } = (0.6) ^{2 - 3x} \\ \\ \implies{ \sqrt{ \frac{5}{3} } } = (0.6)^{2 - 3x} \\ \implies{ \sqrt{ \frac{5}{3} } } = ( \frac{6}{10} )^{2 - 3x} \\\implies{ \sqrt{ \frac{5}{3} } } = ( \frac{3}{5} )^{2 - 3x}$

$\implies \sqrt{ \frac{5}{3} } = [( \frac{5}{3} )^{ - 1} ]^{2 - 3x}$

$\implies \sqrt{ \frac{5}{3} } = ( \frac{5}{3} )^{1 \times (2 \times 3x)}$

$\implies \sqrt{ \frac{5}{3} } = ( \frac{5}{3} )^{ - 2 + 3x}$

$\implies( \frac{5}{3} ) ^{ \frac{1}{2} } = ( \frac{5}{3} ) ^{ ( - 2 + 3x)}$

$\implies \frac{1}{2} = - 2 + 3x$

$\implies - 2 + 3x = \frac{1}{2}$

$\implies3x = \frac{1}{2} + 2$

$\implies3x = \frac{5}{2}$

$\implies \: x = \frac{5}{2 \times 3}$

$\therefore \: x = \frac{5}{6}$

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