Question

root 8 +4 root 32-6 root 2​

Answer 1

√8+4√32-6√2

2√2+4√ 16×2-6√2

2√2+4√4×4×2-6√2

2√2+16√2-6√2

2+16-6√2

18-6√2

12√2.....(final answer)

hope this helps!☺❤✌

Answer 2

The expression is $\sqrt{8}+4\sqrt{32}-6\sqrt{2}=12\sqrt{2}$.

Step-by-step explanation:

Given : Expression $\sqrt{8}+4\sqrt{32}-6\sqrt{2}$

To find : Simplify the expression ?

Solution :

Re-write the expression as,

$\sqrt{8}+4\sqrt{32}-6\sqrt{2}=\sqrt{2\times 2\times 2}+4\sqrt{2\times 2\times 2\times 2\times 2}-6\sqrt{2}$

$\sqrt{8}+4\sqrt{32}-6\sqrt{2}=2\sqrt{2}+4\times 2\times 2\sqrt{2}-6\sqrt{2}$

$\sqrt{8}+4\sqrt{32}-6\sqrt{2}=2\sqrt{2}+16\sqrt{2}-6\sqrt{2}$

$\sqrt{8}+4\sqrt{32}-6\sqrt{2}=(2+16-6)\sqrt{2}$

$\sqrt{8}+4\sqrt{32}-6\sqrt{2}=12\sqrt{2}$

Therefore, the expression is $\sqrt{8}+4\sqrt{32}-6\sqrt{2}=12\sqrt{2}$.

#Learn more

Is root 2 +root 6 =root 8?

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