Question

Root (a+b) whole square identity

Answer 1

$= > \sqrt{(a + b)^{2} }$



$= >(a + b)^{ \frac{1}{2} \times 2 }$


$= > (a + b)^{1}$


=> a+b


I hope this will help you


-by ABHAY

Answer 2

√(a+b)^2
= (a+b)^1
= a+b

Hope this will help you.