Question

root of equation √1 =x-2​

Answer 1

√1=x-2

1=(x-2)²

1=x²-2x+2²

1=x²-2x+4

:.4-1 =x²-2x

3=x²-2x

-x²+2x-3=0

-(x²-2x+3)=0

x²-2x+3=0