Question

root of quadratic equation is 4 minus root 7 find the equation ​

Answer 1

Answer:

$x^{2}$-8x+9

Step-by-step explanation:

Let the quadratic equation be,

$ax^{2}$+ bx+c

We know that one root is, 4-$\sqrt{7}$, hence the other root will be, 4+$\sqrt{7}$.

We know that,

x=4-$\sqrt{7}$ and x=4+$\sqrt{7}$

So, to get the equation we multiply the factors, i.e,

[x-(4-$\sqrt{7}$)] multiplied with [x+(4+$\sqrt{7}$)]

[x-(4-$\sqrt{7}$)] . [x+(4+$\sqrt{7}$)]

$x^{2}$-4x-$\sqrt{7}x$-4x+16+4$\sqrt{7}$+$\sqrt{7}x$-4$\sqrt{7}$-7

Simplifying it we get,

$x^{2}$-8x+9 (ANSWER)

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