Question

root of the quadratic equation x²-3x-10 is​

Answer 1

Answer:

X^2-3x-10

X^2- 5x +2x -10

X( x-5)+2(x-5)

(X-5)(x+2)

So

X-5=0. X+2=0

X=5 x=-2 r the roots

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given, x^2-3x-10=0

x^2-5x+2x-10=0

x(x-5)+2(x-5)=0

(x+2) (x-5)=0

Now solve the value of x,

x+2=0

x= -2

Again,

x-5=0

x= 5

therefore teo roots of quadratic equation x^2-3x-10 is -2 and 5

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