Question

Root x minus 1 ka whole square is equal to 8 minus root 28 solution

Answer 1

Step-by-step explanation:

${( \sqrt{x } - 1) }^{2} = 8 - \sqrt{28} \\ { (\sqrt{x} - 1)}^{2} = 8 - 2 \sqrt{7}$

Now let's do some work with the R. H. S.,

$8 - 2 \sqrt{7} \\ = 1 + 7 + - 2 \sqrt{7} \\ = {1}^{2} + { \sqrt{7} }^{2} - (2)( \sqrt{1} \sqrt{7} ) \\ = {(1 - \sqrt{7} )}^{2}$

And now continue the actual calculation,

${ (\sqrt{x} - 1)}^{2} = {(1 - \sqrt{7} )}^{2} \\ \sqrt{x} - 1 = \sqrt{7} - 1 \\ \sqrt{x} = \sqrt{7} \\ x = 7$

I have done the most elementary calculations.

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