Question

root x +y=7 and x+root y=11 then find x and y​

Answer 1

x+√y=11... .[.1 ] .  

√x+y= 7.......[2] .  

from equation [1] √y=11--x .so y= 121--22x+x^2  

we can substititute this value of y in equation[2]  

√x +121 --22x+x^2=7  

√x = --121+-22x--x^2+7  

solving irt by trial & error method  

if WE HAVE x==9  

THEN, WE HAVE LHS=√x==√9==3..............[A]  

& RHS=-121 +[22X9]--81= -121 +198 -81= 3...[B]  

COMPARING BOTH QUANTITITIES  

WE FIND LHS=RHS  

HENCE x=9 is the correct solution  

Now we can have y=7--√x= 7--√9=7--3=4  

hence the required value  

0f x=9  

& y=4

Hope this helps

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