(root11_root7)(root11+root7) solve this
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Step-by-step explanation:
( root11_root7) ( root 11+root7)
=(root11) square_(root7)square
=11_7=4
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Answered by
2
Answer:
=(√11 -√7) (√11+√7)
[by (a-b)(a+b)= a^2 - b^2]
=(√11)^2-( √7)^2
=11-7
=4
therefore 4 is the answer....
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