Question

(root2+root3)/(3 root 2 - root2 root 3) = a - b root 6.
Find a and b.
plz solve by rationalisation...

Answer 1

here typing mistake , I think
question is
(√2 + √3)/( 3√2 -2√3) = a -b√6

( √2 + √3)( 3√2 + 2√3)/{ (3√2)² - (2√3)² }

(6 + 3√6 + 2√6 + 6 )/( 18 - 12)

(12 + 5√6)/6

2 +( 5/12)√6 = a - b√6

so, a = 2 and b = - 5/12

Answer 2

hai friend,

here is your answer,

√2+ √3 /3 √2 - 2√3=a-b√6

√2+√3/√18-√12=a-b√6

(√2+√3/√18-√12)*(√18+√12/√18+√12)= a-b√6

√2+√3*√18+√12/ 18-6= a-b√6

6+√24+√54+√36/12= a-b√6

12+2√6+3√6/12 =a-b√6

1+5/12√6= a-b√6
1-(-5/12)√6= a-b√6

a=1 , b= -5/12

hope helped

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