Question

root24by 8+root54 by 12

Answer 1

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Given that,

$= > \frac{ \sqrt{24} }{8} + \frac{ \sqrt{54} }{12} \\ \\ = > \frac{\sqrt{2 \times 2 \times 2 \times 3} }{8} + \frac{ \sqrt{2 \times 2 \times 13} }{12} \\ \\ = > \frac{2 \sqrt{6} }{8} + \frac{2 \sqrt{13} }{12} \\ \\ = > \frac{ \sqrt{6} }{4} + \frac{ \sqrt{13} }{6} \\ \\ = > \frac{3 \sqrt{6} + 2 \sqrt{13} }{12}$

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I hope it will help you a lot

thanks

@drsm