Question

root25/ cuberoot 64+(256/625)^-1/4+1/(64/125)^^-2/4

Answer 1

Answer:

Step-by-step explanation:

Here

$\frac{\sqrt{25} }{\sqrt[3]{64} } +\frac {\sqrt[4]{625} }{\sqrt[4]{256}} + \frac{\sqrt{64} }{\sqrt{125} }$

5/4 + 5 /4 + 8/5√5

5/2+8/5√5

25√5+16/10√5