root2x^2+7x+5root2=0 by factorisation method
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√2x^2+7x+5√2=0
Or, √2x^2+5x+2x+5√2=0
Or,x(√2x+5)+√2(√2x+5)=0
Or, (√2x+5)(x+√2)=0
Therefore either √2x+5=0
Or, √2x= -5
Or, x= -5/√2
/OR x+√2=0
Or, x= -√2
Or, √2x^2+5x+2x+5√2=0
Or,x(√2x+5)+√2(√2x+5)=0
Or, (√2x+5)(x+√2)=0
Therefore either √2x+5=0
Or, √2x= -5
Or, x= -5/√2
/OR x+√2=0
Or, x= -√2
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