root2xsquar+7x+5root2 =0 by middle term spliting
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Solution:
Given Quadratic equation,
√2x² + 7x + 5√2 = 0
Splitting the middle term , we get
=> √2x² + 2x + 5x + 5√2 = 0
=> √2x²+ √2*√2x+5x+5√2 = 0
=> √2x( x + √2 ) + 5( x + √2 ) = 0
=> ( x + √2 )( √2x + 5 ) = 0
Therefore ,
x + √2 = 0 or √2x + 5 = 0
x = -√2 or x = ( -5 )/√2
••••
Given Quadratic equation,
√2x² + 7x + 5√2 = 0
Splitting the middle term , we get
=> √2x² + 2x + 5x + 5√2 = 0
=> √2x²+ √2*√2x+5x+5√2 = 0
=> √2x( x + √2 ) + 5( x + √2 ) = 0
=> ( x + √2 )( √2x + 5 ) = 0
Therefore ,
x + √2 = 0 or √2x + 5 = 0
x = -√2 or x = ( -5 )/√2
••••
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