Root3 tan4theta-3=0 find theta
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√3 * tan4 theta -3 = 0
➡ √3tan 4theta = 3
➡ tan 4theta = 3/√3
➡ tan4 theta = √3
➡ We know that, tan 60° = √3
➡ so, tan 4 theta = tan 60°
➡ 4 theta = 60°
➡ theta = 60/4
➡ theta = 15°
Hope it will help you !!!
➡ √3tan 4theta = 3
➡ tan 4theta = 3/√3
➡ tan4 theta = √3
➡ We know that, tan 60° = √3
➡ so, tan 4 theta = tan 60°
➡ 4 theta = 60°
➡ theta = 60/4
➡ theta = 15°
Hope it will help you !!!
Answered by
2
Trigonometry,
Let 'a' instead of theta,ok
we have,

or, √3tan(4a) = 3
or, tan(4a) = 3/√3
or, tan(4a) = √3
or, tan(4a) = tan60° [as we know that tan60° = √3]
So, 4a (4theta) = 60°
Therefore theta is equal to 60°/4 = 15°.
That's it
Hope it helped ლ(´ڡ`ლ)
Let 'a' instead of theta,ok
we have,
or, √3tan(4a) = 3
or, tan(4a) = 3/√3
or, tan(4a) = √3
or, tan(4a) = tan60° [as we know that tan60° = √3]
So, 4a (4theta) = 60°
Therefore theta is equal to 60°/4 = 15°.
That's it
Hope it helped ლ(´ڡ`ლ)
Attachments:
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