Math, asked by Muskangupta9544, 11 months ago

Root3x-2=2root3+4 value of x is

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Answered by umiko28
3

Step-by-step explanation:[tex] \sqrt{3x} - 2 = 2 \sqrt{3 } + 4 \\ \\ \sqrt{3x } = 2 \sqrt{3} + 6 \\ x = 2 \sqrt{3} + 6 \div \sqrt{3} \\ x = 2 + \frac{6}{ \sqrt{3} } \\ x = 2 + (\sqrt{2} \times \sqrt{3} ) \div \sqrt{3} \: \\ x = 2 + \sqrt{2 } \\ \\

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