Question

root3x²-2x+1/2=0 quadratic equation are not

Answer 1

$\sqrt{3} {x}^{2} - 2x + \frac{1}{2} = 0 \\ = > \frac{2 \sqrt{3} {x}^{2} - 4x + 1}{2} = 0 \\ = > 2 \sqrt{3} {x}^{2} - 4x + 1 = 0 \\ we \: have \\ d = {b}^{2} - 4ac \\ = > d = { - 4}^{2} - 4 \times 2 \sqrt{3} \times 1 \\ = > d = 16 -8 \sqrt{3} \\ = > d = 8(2 - \sqrt{3}) \\ this \: equation \: does \: not \: exist$

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