root5-2/root5+2 + root5 +2/root5-2
Answers
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0
Answer:
Rationalize the denominator.
\frac{\sqrt{5}-2}{\sqrt{5}+2}\times\frac{\sqrt{5}-2}{\sqrt{5}-2}-\frac{\sqrt{5}+2}{\sqrt{5}-2}\times\frac{\sqrt{5}+2}{\sqrt{5}+2}
5
+2
5
−2
×
5
−2
5
−2
−
5
−2
5
+2
×
5
+2
5
+2
\frac{(\sqrt{5}-2)^2}{5-4}-\frac{(\sqrt{5}+2)^2}{5-4}
5−4
(
5
−2)
2
−
5−4
(
5
+2)
2
5-4\sqrt{5}-(5+4\sqrt{5})5−4
5
−(5+4
5
)
5-4\sqrt{5}-5-4\sqrt{5}5−4
5
−5−4
5
-8\sqrt{5}−8
5
Therefore the value of given expression is -8\sqrt{5}−8
5
.
Answered by
0
Answer:
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