Question

root5+root3/root5 - root3 evaluate

Answer 1

$\sqrt{5 } + \frac{ \sqrt{3} }{ \sqrt{5} } - \sqrt{3} = 5 + \sqrt{3} (1 - \sqrt{5} ) =$
which is equal to...i dont know without using calculator

Answer 2

$\frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } \\ \frac{( \sqrt{5} + \sqrt{3} ) {}^{2} }{( \sqrt{5} ) {}^{2} - { (\sqrt{3} )}^{2} } \\ \frac{5 + 3 + 2 \sqrt{15} }{2} \\ \frac{8 + 2 \sqrt{15} }{2} \\ 4 + \sqrt{15}$

For this Question, we can rationalize the denominator as above,