Question

root7 root7 root7 root7 root7= 7^x, find the value of x.​

Answer 1

Answer:

when √x is repeated n times , than its value given by x^(2^n-1) ÷ 2^n

so ,

here n = 5 and x = 7

so ,

7^(2^5-1) ÷ 2^5

7^31/32

for clear vision see the attachment

Answer 2

root 7 root 7 root 7 root 7 root7 = 7^x

(root 7 * root 7) (root 7 *root 7)root7= 7^x

(7)(7) 7^(1/2) = 7^x

7^2 * 7 ^(1/2) = 7^x

7^(2 + 1/2) = 7^x

7^(5/2) = 7^x

5/2 = x