Question

roots of equation p(q-r)x^2+q(r-p)x+r(p-q)=0 are equal then show that 1/p+1/r=2/q

Answer 1

roots equal
so
D=0
b^2 - 4ac=0
q^2(r-p)^2 - 4{p(q-r)}{r(p-q)}
after opening brackets
you can get the result 1/p + 1/r = 2/q