Question

Roots of quadratic equation xsquare-5ix-6=0are

Answer 1

Answer:

Step-by-step explanation:

The question is inappropriate cause it is 5ix

Answer 2

x2-5x-6=0

terms to be added,

=[1/2 coefficient of x]square

=[1/2 ×-5]square

=[1/4 × 25]

=25/4

therefore, x2-5x+25/4 - 25/4 - 6 =0

[ x-5/4]square=25/4+6

[ x-5/4]square=25+24/4

[ x-5/4]square=49/4

[ x-5/4] =7/2 [taking square roots]

x=5/4 +- 7/2

x=5+14/4 or x=5-14/4

x=19/4 or x= -11/4

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