Math, asked by vinay310, 1 year ago

roots of
 \sqrt{2}  {x}^{2}  - 3x + 3 \sqrt{2} = 0

Answers

Answered by SnehaG
30
hello

Heya !!

The given equation is

→√2x²-3x+3√2

Here,

a = √2 ,
b = -3
and
c = 3√2.

Discriminant ( D ) = B²-4AC

=> (-3)²-4×√2×3√2

=> 9-24

=> -13

since,discriminant is less than zero

no:/  real  :/roots    :/exists
hope \: it \: helps

SnehaG \: { { \gamma }^{ \gamma } }^{ \gamma }

pkparmeetkaur: :)
Answered by Anonymous
3

HELLO MATE ❤❤❤

Here,

a = √2 ,

b = -3

and

c = 3√2.

Discriminant ( D ) = B²-4AC

=> (-3)²-4×√2×3√2

=> 9-24

=> -13

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