Round disc of moment of inertia i2 about its axis perpendicular to its plane and passing through its centre is placed over another disc of moment of inertia i want rotating with an angular velocity omega about the same access the final angular velocity is a combination of discuss
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The angular momentum is ω' = L1 ω/ I1 + I2
Explanation:
Angular momentum of a disc of moment of inertia I1 and rotating about its axis with angular velocity is
L1=I1ω
When a round disc of moment of inertia I2 is placed of first disc, then angular momentum of the combination is
L2=(I1+I2)ω'
Angular momentum remains conserved, in the absence of any external force.
L1 = L2
I1ω=(I1+I2)ω'
ω' = L1 ω/ I1 + I2
Thue the angular momentum is ω' = L1 ω/ I1 + I2
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