Science, asked by rk5252, 11 months ago

round two compound X is formed by the reaction of carboxylic acid C2 H4 O2 and an alcohol in the sense of a few drops of H2 s o4 the alcohol on oxidation with alkaline kmn o4 and followed by acidification gives the same carboxylic acid as used in the this reaction give the name and structure of a) carboxylic acid b) alcohol and c) the compound x.also write the reaction. plzzz fast​

Answers

Answered by MilanKumar17
1

Answer:

X IS ETHYL ETHNOATE ( ESTER)

IT IS FORMED WHEN

CH³COOH + C²H5OH → CH³COOC²H5 + H²0

NEXT

C²H5OH + KMnO⁴ → CH³COOH

(EHTANOL). (ETHANOIC ACID)

PLS MAKE THE STRUCTURE OF ESTER IT IS TOO EASY,

MARK AS BRAINLIST IF POSSIBLE PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS...

Attachments:
Answered by skdhabalp9qhj0
0

Answer:

A. Name : ethanoic acid

B. Name: ethanol

C. X =ester

CH3 c o o h + CH3 ch 2 ch becomes CH3 c o o ch2 CH3 + H2O

Explanation:

Similar questions