Question

Roy is twice as old as Joan, and in 3 years the sum of their ages will be 21 years. Find their present ages.

Answer 1

Answer:

Roy=10     Joan=5

Step-by-step explanation:

Let's say Joan's age is 5, then Roy's age will be = Joan's age*2=5*2=10

After 3 years their ages will be= Joan=5+3=8 and Roy=10+3=13

so the sum is = 8+13=21

hence, roys current age is 10 and joan's is 5

pls mark as brainliest

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The present ages of Roy and Jaon are 10 and 5 respectively.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Roy is = twice the age of Joan

3 years later, Sum of their ages = 21

To find :

Their present ages

Solution :

Consider the Present age of Jaon as x

Roy's present age = 2x

Ages After 3 Years -

Joan = x + 3

Roy = 2x + 3

★ $\boxed{\sf{(x+3)+(2x+3)=21}}$

$\sf{\implies} \: (x + 3) + (2x + 3) = 21$

$\sf{\implies} \: x + 3 + 2x + 3 = 21$

$\sf{\implies} \: 3x + 6= 21$

$\sf{\implies} \: 3x = 21 - 6$

$\sf{\implies} \: 3x = 15$

$\sf{\implies} \: x = \dfrac{15}{3}$

$\sf{\implies} \: x = 5$

$\rule{300}{1.5}$

Jaon = 5 years

★ Value of 2x

$\sf{\implies} \: 5 \times 2$

$\sf{\implies} \: 10$

$\therefore$ The present ages of Roy and Jaon are 10 and 5 respectively.

$\rule{300}{1.5}$

$\mathfrak{\large{\underline{\underline{Verification :-}}}}$

$\sf{\implies} \: 5+ 3 + (5 \times 2)+ 3 = 21$

$\sf{\implies} \: 8 + 10 + 3 = 21$

$\sf{\implies} \:21= 21$

$\therefore$ The present ages of Roy and Jaon are 10 and 5 respectively.