Question

ΔRPQ is a right angled at Q. If PQ = 5 cm and RQ = 10 cm, find sinP. ​

Answer 1

PQ^2 + RQ^2 = RP^2

RP^2 = 10^2 + 5^2

= 100 + 25

= 125

RP = Root 125

Sin P = Opposite Side/Hypotenuse

= RQ/RP

= 10/ Root 125

$10 \div \sqrt{125}$

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