Math, asked by adityadeep453, 6 months ago

y^2 + 19 y - 150 factorise​

Answers

Answered by XxMissPaglixX
20

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Answered by joelpaulabraham
1

Answer:

(y + 25)( y - 6)

Step-by-step explanation:

y² + 19y - 150 is an expression, that is, there is no equal to( = )

so, By factoring the middle term method

y² + 19y - 150

ay² + by - c, where a, b, and c are coefficients

Now,

Sum = b = 19

Product = (a×c) = -150

So we must find a number which adds to 19 and gives a product -150

Factors of 150 are 1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150

Now when we look into the product and sum, the factors must be a positive and a negative value

also, by trial and error we come to the conclusion factors are 25 and -6

Therefore, = y² + 25y - 6y - 150

Taking commons we get

=y(y + 25) -6(y + 25)

=(y + 25)(y - 6)

Hope you understood it........All the best

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