Question

Rs. 2100 is lent at compound interest of 5% per annum for 2 years. Find the amount after two years.
A.Rs. 2300
B.Rs. 2315.25
C.Rs. 2310
D.Rs. 2320

Answer 1

______✨ HEY MATE ✨______

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SOLUTION :-
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We can use formula of compound interest;
A = P*[1+ (r/100)]n 
A = 2100*[1+(5/100)]2
A = 2100*[105/100]2
A = (2100*11025)/10000
Hence, Amount, A = Rs. 2315.25.

So , Option (B) is the right answer ✔️

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Answer 2

Hey mate ^_^

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Answer:
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Compound interest,

$A= P[1 + (\frac{r}{100} )] ^{n}$

$A = 2100 \times [(1 + ( \frac{5}{100} )] ^{2}$

$A = 2100 \times ( \frac{105}{100} ) ^{2}$

$A= \frac{(2100 \times 11025)}{10000}$

$A = \frac{23152500}{10000}$

$A = 2315.25$

Hence,

Amount,

$A = Rs. 2315.25$

Therefore,

Correct option B) Rs. 2315.25

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