Question

the point on the x-axis which is equidistant from (2,-5) and (-2,9) is:

Answer 1

Hi ,

Let the P( x , 0 ) is a point which is equidistant

from A( 2 , -5 ) and B ( -2 , 9 ).

AP = BP

AP² = BP²

( x - 2 )² + [ 0 - ( - 5 ) ]² = [ x - ( -2 ) ]² + ( 0 - 9 )²


x² - 4x + 4 + 25 = x² + 4x + 4 + 81

- 4x - 4x = 85 - 29

- 8x = 56

x = 56/ ( -8 )

x = - 7

Therefore ,

Required point = ( x , 0 ) = ( - 7 , 0 )

I hope this helps you.

: )