Rukhsar painted the outside of the cabinet of measure 1m×2m×1.5m.How much surface area did she cover if she painted all except the bottom of the cabinet
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Answered by
40
Surface Area of Cabinet = 2(lb + lh + bh)
= 2(1 x 2 + 1 x 1.5 + 1.5 x 2)
= 2(2 + 1.5 + 3) = 2 x 6.5 = 13
Area of Bottom Surface = 1 x 2 = 2 sq m
Area Covered by painting = 13-2
= 11 sq m
= 2(1 x 2 + 1 x 1.5 + 1.5 x 2)
= 2(2 + 1.5 + 3) = 2 x 6.5 = 13
Area of Bottom Surface = 1 x 2 = 2 sq m
Area Covered by painting = 13-2
= 11 sq m
Answered by
8
GIVEN :-
• Length of cabinet = 2m
• Breath of cabinet = 1m
• Height of cabinet = 1.5m
TO FIND :-
• Surface did raju paint.
SOLUTION :-
We know that,
Now,
⟶ Area painted by raju = 2lh + 2bh + lb.
[ Put the values ]
⟶ Area painted by raju = 2( 2×1.5) + 2(1×1.5) + (2×1)
⟶ Area of painted by raju = 6 + 3 + 2
⟶ Area of painted by raju = 11m².
Therefore, the area painted by raju is 11m².
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