Question

Running at 7/11th of his usual speed, an athlete is late by 10 minutes.how much time he normally takes to run the distance?

Answer 1

Answer:

Normal time required is 17.5 hours.

Step-by-step explanation:

We know that, Speed = (Distance/Time)

Or, Distance = (Speed × Time)

Let the speed of running = S.

Time required = T.

Also if speed becomes (7/11) S then time required =(T+10).

As per question,

ST = (7/11) S× (T+10)

T = (7/11) (T+10)

(11/7) T= T +10

(4/7) T = 10

T =(10×7) /4

T=70/4=17.5 hours.