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6.Solve sin 4x • cos 3xdx
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Answered by
1
Answer:
Step-by-step explanation:
=
∫
cos
3
x
⋅
sin
4
x
d
x
=
∫
cos
x
⋅
cos
2
x
⋅
sin
4
x
d
x
=
∫
cos
x
⋅
(
1
−
sin
2
x
)
⋅
sin
4
x
d
x
Let
u
=
sin
x
, so
d
u
=
cos
x
d
x
, and
d
x
=
d
u
cos
x
:
=
∫
cos
x
⋅
(
1
−
u
2
)
⋅
u
4
⋅
d
u
cos
x
=
∫
cos
x
⋅
(
1
−
u
2
)
⋅
u
4
⋅
d
u
cos
x
=
∫
(
1
−
u
2
)
⋅
u
4
d
u
=
∫
(
u
4
−
u
6
)
d
u
=
∫
u
4
d
u
−
∫
u
6
d
u
=
u
5
5
−
u
7
7
+
C
=
7
u
5
−
5
u
7
35
+
C
=
7
sin
5
x
−
5
sin
7
x
35
+
C
That's the integral. Hope this helped!
prakashjadhav76:
hii
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