Russell had thirty 20¢ and 10¢ coins. He exchanged all the 10c coins
for 20¢ coins and had a total of eighteen 20¢ coins after the exchange.
How many 10¢ coins did he have at first?
Answers
Answered by
3
Answer:
6828×2992+9292×3838+4884÷747474×7374+7272×83838+8383-3773-6446×552+8×*22
Similar questions