Rx - y = 2, 6x- 2y = 3 find the value of R
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For a system of equations a1x+b1y+c1=0;a2x+b2y+c2=0 to have unique solution, the condition to be satisfied is
a2a1=b2b1=c2c1
⇒6k=−2−1=32
∴ For unique solution of system of equations, k=3,4
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